Script to find if a number is odd or even using the command factor.

Here is linux shell script which will find if a number is even or odd using the command factor.

#!/bin/bash echo "Enter the number" read x res=$(factor $x | grep -c 2) if [ $res -eq 0 ] then echo "The number is odd" else echo "The number is even" fi

Save the script as oddEven.sh and execute it using bash.

$ bash oddEven.sh Enter the number 32 The number is even

The factor command basically lists all the factors of the number, and by using grep we search for 2 using the option -c to count if 2 is present count will be 1 , else it will be 0.